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Manipal Medical Manipal Medical Solved Paper-2010

  • question_answer
    The effective atomic number of\[Cr\](atomic no. 24) in\[[Cr{{(N{{H}_{3}})}_{6}}]C{{l}_{3}}\]is

    A)  35            

    B)  27

    C)  33             

    D)  36

    Correct Answer: C

    Solution :

     Effective atomic number, BAN = number of electrons in\[Cr+2\times \]number of      ligands \[-\] charge \[=24+2\times 6-3=33\]


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