A) \[2.1\times {{10}^{-34}}J-s\]
B) \[3\times {{10}^{-34}}J-s\]
C) \[2\times {{10}^{-34}}J-s\]
D) \[0.5\times {{10}^{-34}}J-s\]
Correct Answer: A
Solution :
\[-3.4=-\frac{13.6}{{{n}^{2}}}\Rightarrow n=2\] \[\therefore \] \[L=\frac{2\times 6.6\times {{10}^{-34}}}{2\times 3.14}=2.1\times {{10}^{-34}}J-s\]
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