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Manipal Medical Manipal Medical Solved Paper-2009

  • question_answer
    A ball of mass 0.5 kg moving with a velocity of \[2\text{ }m{{s}^{-1}}\]strikes a wall normally and bounces back with the same speed. If the time of contact between the ball and wall is\[{{10}^{-3}}s,\]the average force exerted by the wall on the ball is

    A)  1125N        

    B)  1000 N

    C)  500 N          

    D)  2000 N

    Correct Answer: D

    Solution :

    Impulse \[=\text{ }mv-(-mv)\] \[=0.5\times 2-(-0.5\times 2)=2\] Hence,   \[F=\frac{2}{{{10}^{-3}}}=2000\text{ }N\]


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