Manipal Medical Manipal Medical Solved Paper-2006

  • question_answer
    After 2 hours 1/16th of initial amount of a certain radioactive isotope remains undecayed. The half-life of the isotope is:

    A)  15min         

    B)  30 min

    C)  45 min         

    D)  60 min

    Correct Answer: B

    Solution :

     \[N={{N}_{0}}{{\left( \frac{1}{2} \right)}^{n}}\] \[\frac{{{N}_{0}}}{16}={{N}_{0}}{{\left( \frac{1}{2} \right)}^{n}}\] \[\Rightarrow \] \[{{\left( \frac{1}{2} \right)}^{4}}={{\left( \frac{1}{2} \right)}^{n}}\] \[(\therefore n=4)\] Half-life\[=\frac{Total\,time}{n}\] \[=\frac{2}{4}\] \[=0.5h\] \[=30\text{ }min\]


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