A) \[30{}^\circ \]
B) \[45{}^\circ \]
C) \[60{}^\circ \]
D) \[15{}^\circ \]
Correct Answer: A
Solution :
The distance of first diffraction minimum from the central principal maximum. \[x=\frac{D\lambda }{d}\] \[\frac{x}{D}=\frac{\lambda }{d}\] or \[d=\frac{\lambda }{\sin \theta }\] \[\Rightarrow \] \[\sin \theta =\frac{\lambda }{d}=\frac{5000\times 1{{J}^{-8}}}{1\times {{10}^{-4}}}\] \[\sin \theta =0.5=\sin 30\] \[\theta =30{}^\circ \]
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