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Manipal Medical Manipal Medical Solved Paper-2003

  • question_answer
    A body of uniform cross-sectional area floats in a liquid of density thrice its value. The fraction of exposed height will be:

    A)  2/3           

    B) 5/6

    C)  1/6           

    D)  1/3

    Correct Answer: A

    Solution :

     Here area is uniform, so portion of immersed height\[=\frac{1}{3}\] (Here: the ratio of density of body and density of water\[=\frac{1}{3}\]) Therefore, fraction of exposed height will \[1-\frac{1}{3}=\frac{2}{3}\]


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