A) \[0.8268\times {{10}^{-34}}kg\]
B) \[1.2876\times {{10}^{-33}}kg\]
C) \[1.4285\times {{10}^{-32}}kg\]
D) \[1.8884\times {{10}^{-32}}kg\]
Correct Answer: C
Solution :
We know that\[\lambda =\frac{h}{m\upsilon }\] \[\therefore \] \[m=\frac{h}{\lambda \upsilon }\] The velocity of photon \[(\upsilon )=3\times {{10}^{8}}m\text{ }se{{c}^{-1}}\] \[\lambda =1.54\times {{10}^{-8}}cm=1.54\times {{10}^{-10}}metre\] \[\therefore \]\[m=\frac{6.626\times {{10}^{-34}}Js}{1.54\times {{10}^{-10}}m\times 3\times {{10}^{8}}m{{\sec }^{-1}}}\] \[=1.4285\times {{10}^{-32}}kg\]
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