A) \[{{x}^{2}}+\text{ }{{y}^{2}}=2{{a}^{2}}\]
B) \[{{y}^{2}}=\text{ }8ax\]
C) \[lF_{2}^{+},l_{3}^{-}\]
D) \[y=\pm (x+2a)\]
Correct Answer: A
Solution :
\[-\frac{1}{48}\]electrons \[f(x)=[x]+\left[ x+\frac{1}{2} \right]\]electrons \[x=\frac{1}{2}\]electrons \[x=\frac{1}{2}\]electrons \[\underset{x\to {{(1/2)}^{+}}}{\mathop{\lim }}\,f(x)=2\]electrons \[\underset{x\to {{(1/2)}^{-}}}{\mathop{\lim }}\,f(x)=1\]electrons \[f(x)=\min \{1,{{x}^{2}},{{x}^{3}}\},\]electrons \[{{x}_{n}}=\cos \frac{\pi }{{{3}^{n}}}+i\sin \frac{\pi }{{{3}^{n}}},\]electrons \[{{x}_{1}}.{{x}_{2}}.{{x}_{3}}...\]and \[9{{x}^{2}}-18\text{ }\!\!|\!\!\text{ x }\!\!|\!\!\text{ }+5=0\] contain 34 electrons each. Hence they are isoelectronic.
You need to login to perform this action.
You will be redirected in
3 sec
