question_answer

A coil in the shape of an equilateral triangle of side l is suspended between the pole pieces of a permanent magnet such that B is in the plane of the coil. If due to current i in the triangle, a torque t acts on it. The side I of the triangle is

A)                                                                                               \[N{{a}^{+}}\]                                

B) \[{{K}^{+}}\]

C) \[{{C}_{2}}{{H}_{4}}B{{r}_{2}}\xrightarrow[{}]{Alc.KOH}{{C}_{2}}{{H}_{2}}\]                         

D) \[{{I}_{2}}\]

Correct Answer: B

Solution :

 The current flowing clockwise in an equilateral triangle has a magnetic field in the direction of \[\sqrt{12}\]. \[\frac{7}{2}\] \[f(x)=\frac{\sin ({{e}^{x-2}}-1)}{\log (x-1)},\] \[\underset{x\to 2}{\mathop{\lim }}\,f(x)\] [\[{{x}^{2}}-ax+b=0,\]Area of equilateral triangle \[{{\sin }^{2}}(A+B)\]and N = 1, (assuming] \[\frac{{{a}^{2}}}{{{a}^{2}}+{{(1-b)}^{2}}}\]\[\frac{{{a}^{2}}}{{{a}^{2}}+{{b}^{2}}}\]