Manipal Engineering Manipal Engineering Solved Paper-2015

  • question_answer
    In which of the following complex ion, the central matal ion is in a state of \[a{{x}^{2}}+2hxy+b{{y}^{2}}=1,a>0\]hybridisation?

    A) \[\frac{\pi }{4}\]              

    B) \[f(x)=x{{e}^{-x}}\]

    C) \[[0,\infty ),\]                   

    D) \[0\]

    Correct Answer: A

    Solution :

    \[u={{e}^{x}}\sin x\]ion \[v={{e}^{x}}\cos x\]is a weak ligand. It cannot pair up d-electrons and forms outer orbital octahedral complex. \[v\frac{du}{dx}-u\frac{dv}{dx}={{u}^{2}}+{{v}^{2}}\]arid\[\frac{{{d}^{2}}u}{d{{x}^{2}}}=2v\] are strong ligands. So, they pair up d-electrons and form their inner orbital complex. \[\frac{{{d}^{2}}u}{d{{x}^{2}}}=-2u\]ion \[{{\tan }^{-1}}\left( \frac{\sqrt{1+{{x}^{2}}}-1}{x} \right)\]ion (d)\[{{\tan }^{-1}}\left( \frac{2x\sqrt{1-{{x}^{2}}}}{1-2{{x}^{2}}} \right)\]ion


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