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Manipal Engineering Manipal Engineering Solved Paper-2015

  • question_answer
    An electron beam accelerated from rest through a potential 'difference of 5000 V in vacuum is allowed to impinge on a surface normally. The incident current is \[\frac{{{2}^{x}}+{{2}^{y}}}{1+{{2}^{x+y}}}\] and if the electron comes to rest on striking the surface, the force on it is

    A) \[{{2}^{x-y}}\left( \frac{{{2}^{y}}-1}{1-{{2}^{x}}} \right)\]              

    B) \[\frac{{{2}^{x-y}}-{{2}^{x}}}{{{2}^{y}}}\]

    C) \[x-3y=0\]                          

    D) \[x+3y=0\]

    Correct Answer: A

    Solution :

    Energy\[HCl{{O}_{2}}\] \[4M+8C{{N}^{-}}+2{{H}_{2}}O+{{O}_{2}}\] \[\xrightarrow[{}]{{}}4[M{{(CN)}_{2}}]+4O{{H}^{-}}\] \[s{{p}^{3}}{{d}^{2}}\] Number of electrons striking per second is \[{{[Co{{F}_{6}}]}^{3-}}\]\[{{[Co{{(N{{H}_{3}})}_{6}}]}^{3+}}\]\[{{[Fe{{(CN)}_{6}}]}^{3-}}\] Force = Change of momentum per second \[{{[Cr{{(N{{H}_{3}})}_{6}}]}^{3+}}\] \[{{C}_{2}}{{H}_{5}}Cl+KCN\xrightarrow[{}]{{{C}_{2}}{{H}_{5}}OH}X\xrightarrow[\Delta ]{{{H}_{3}}{{O}^{\oplus }}}Y,\]


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