A) both
B) neither
C) photon only
D) electron only
Correct Answer: C
Solution :
Energy is given by\[B{{F}_{3}}>BC{{l}_{3}}>BB{{r}_{3}}>B{{l}_{3}}\] \[BC{{l}_{3}}>B{{F}_{3}}>B{{l}_{3}}>BB{{r}_{3}}\]\[{{C}_{7}}{{H}_{8}}\xrightarrow[{}]{3C{{l}_{2}},heat}A\xrightarrow[{}]{Fe/{{B}_{r2}}}B\xrightarrow[{}]{Zn/HCl}C\]Momentum P is given by \[C{{l}_{2}}\]\[OCl\] \[O{{F}_{2}}\]\[{{O}_{2}}{{F}_{2}}\]\[Zn\xrightarrow[{}]{{}}Z{{n}^{2+}}+2{{e}^{-}};{{E}^{o}}=+0.76V\]\[F{{e}^{2+}}+2{{e}^{-}}\xrightarrow[{}]{{}}Fe\,;{{E}^{o}}=+0.41\] For photon,, rest mass \[F{{e}^{2+}}+Zn\xrightarrow[{}]{{}}Z{{n}^{2+}}+Fe\]so\[{{N}_{2}}+3{{H}_{2}}2N{{H}_{3}};+22kcal\] For electron, \[N{{a}^{+}}>A{{l}^{3+}}>B{{a}^{2+}}\]so\[PO_{4}^{3-}>SO_{4}^{2-}>C{{l}^{-}}\]
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