A) \[\left( x+\frac{1}{{{x}^{2}}} \right),\]
B) \[{{\sin }^{-1}}\left\{ \cos \left( {{\sin }^{-1}}\sqrt{\frac{2-\sqrt{3}}{4}} \right. \right.\]
C) \[\left. \left. +{{\cos }^{-1}}\frac{\sqrt{12}}{4}+{{\sec }^{-1}}\sqrt{2} \right) \right\}\]
D) \[\frac{\pi }{4}\]
Correct Answer: B
Solution :
The current through the circuit before the battery of emf \[{{y}^{2}}=\text{ }8ax\]short circuited, is \[x=\pm (y+2a)\] ...(i) After short circuiting the battery of emf \[y=\pm (x+2a)\] current through the resistance R would be \[x=\pm (y+a)\]Since, from Eqs. (i) and (ii), we get \[y=\pm (x+a)\] \[x+y+z=1\]\[2x+3y-z+4=0\] This gives\[y-3z+6=0\]
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