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Manipal Engineering Manipal Engineering Solved Paper-2015

  • question_answer
    \[\underset{x\to -1}{\mathop{\lim }}\,{{\left( \frac{{{x}^{4}}+{{x}^{2}}+x+1}{{{x}^{2}}-x-1} \right)}^{\frac{1-\cos (x+1)}{{{(x+1)}^{2}}}}}\]is equal to

    A) 1                                             

    B) \[S=2.5\Omega ,G=25\Omega ,\]

    C) \[\frac{i}{{{i}_{0}}}=\frac{1}{11}\]                                            

    D) \[\because \]

    Correct Answer: B

    Solution :

    We observe that \[E=\frac{-13.6}{{{(5)}^{2}}}eV=-0.54eV\]as\[iG=(i-{{i}_{0}})S\] But\[{{i}_{0}}\]as\[\frac{i}{{{i}_{0}}}=\frac{S}{G+S}\] \[S=2.5\Omega ,G=25\Omega ,\]\[\frac{i}{{{i}_{0}}}=\frac{1}{11}\] \[\because \]


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