Manipal Engineering Manipal Engineering Solved Paper-2015

  • question_answer
    The approximate value of\[a\times b\] is

    A) 1.2                                         

    B) 1.4

    C) 1.6                                         

    D) 1.8

    Correct Answer: C

    Solution :

    Ley\[{{c}^{2}}-3c-7=0\]and \[{{c}^{2}}+3c+7=0\] Then,\[{{c}^{2}}-3c+7=0\] Also, y = 1, when x = 1 Now,\[{{c}^{2}}+3c-7=0\] \[\frac{3}{{{1}^{2}}}+\frac{5}{{{1}^{2}}+{{2}^{2}}}+\frac{7}{{{1}^{2}}+{{2}^{2}}+{{3}^{2}}}+...,\]\[\frac{6n}{n+1}\]\[\frac{9n}{n+1}\]\[\frac{12n}{n+1}\] \[\frac{3n}{n+1}\]\[\int_{\sqrt{\ln 2}}^{\sqrt{\ln 3}}{\frac{x\sin {{x}^{2}}}{\sin {{x}^{2}}+\sin (\ln 6-{{x}^{2}})}dx}\] \[\frac{1}{4}\ln \frac{3}{2}\]\[\frac{1}{2}\ln \frac{3}{2}\] Hence,\[\ln \frac{3}{2}\]


You need to login to perform this action.
You will be redirected in 3 sec spinner