Manipal Engineering Manipal Engineering Solved Paper-2015

  • question_answer
    The two blocks of masses \[K{{l}_{2}}\] and \[{{l}^{-}}\]are kept on a smooth horizontal table as shown in the figure. Block of mass \[{{K}^{+}};{{l}^{-}}\] but not \[{{l}_{2}}\] is fastened to the spring. If now both the blocks are pushed to the left, so that the spring is compressed at a distance d. The amplitude of oscillation of block of mass \[l_{3}^{-}\] after the system released, is

    A) \[{{(1.0002)}^{3000}}\]                 

    B) \[(a.\hat{i})(a\times \hat{i})+(a.\hat{j})(a\times \hat{j})+(a.\hat{k})(a\times \hat{k})\]

    C) \[A=\{(x,y):{{x}^{2}}+{{y}^{2}}=25\}\]                   

    D) \[B=\{(x,y):{{x}^{2}}+{{y}^{2}}=144\};\]

    Correct Answer: A

    Solution :

     Block of mass \[\frac{{{a}^{2}}}{{{(a+b)}^{2}}}\]shoots off carrying some kinetic energy away from the system. To find its speed, potential energy of spring = maximum kinetic energy of blocks. \[\frac{{{a}^{2}}}{{{b}^{2}}+{{(1-a)}^{2}}}\]  [k = force constant of spring] \[\Delta ABC,\] with \[{{a}^{2}}+{{b}^{2}}+{{c}^{2}}=ac+\sqrt{3}ab,\] along on the spring. Maximum potential energy = Maximum kinetic energy of \[(a\times b)\times c=\frac{1}{3}|b|\,\,|c|\] \[\theta \]\[\theta \] \[\frac{2\sqrt{2}}{3}\]\[\frac{\sqrt{2}}{3}\]


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