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Manipal Engineering Manipal Engineering Solved Paper-2014

  • question_answer
    Equal moles of \[\frac{{{\sin }^{2}}(a+y)}{\cos a}\] and N.O(g) are to be placed in a container to produce \[\frac{{{\cos }^{2}}(a+y)}{\sin a}\] according to the reaction, \[f(x)={{x}^{3}}-7{{x}^{2}}+15,\] How many moles of \[f(x)={{x}^{3}}-3{{x}^{2}}+2x\] and NO be placed in the 5.0 L container to have an equilibrium concentration of \[c=\pm 1\]to be 0.05 M?

    A) 0.5115                  

    B) 0.1023  

    C)  0.0526                                 

    D) 0.2046

    Correct Answer: A

    Solution :

    Equilibrium concentration of \[{{[Fe{{({{H}_{2}}O)}_{5}}NO]}^{2+}}\] Let the equilibrium concentration of \[FeS{{O}_{4}}\] and NO be x M \[NO_{3}^{-}\] Initial concentrations of \[{{H}_{2}}S{{O}_{4}}.\] and NO were 0.05 + x = 0.1022 M each. Hence, moles of each gas \[F{{e}^{2+}}\] and NO taken initially  \[F{{e}^{3+}}\]


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