A) \[\frac{500}{729}\]
B) \[\frac{600}{729}\]
C) \[{{7}^{m}}+{{7}^{n}}\]
D) \[\frac{1}{4}\]
Correct Answer: C
Solution :
In \[SOC{{l}_{2}}\] let 'x' be the oxidation number of S. Thus, the element X may be bromine. 4 x ? 12 = - 2 \[{{C}_{2}}{{H}_{5}}Cl,AlC{{l}_{3}}\]
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