Manipal Engineering Manipal Engineering Solved Paper-2014

  • question_answer
    Number of particles is given by \[2{{a}^{3}}\]crossing a unit area perpendicular to X-axis is unit time, where \[\sqrt{5}-\sqrt{6}\] and \[\sqrt{5}+\sqrt{6}\]are number of particles per unit volume for the value of x meant to \[\sqrt{5}\pm \sqrt{6}\]and \[5\pm \sqrt{6}\]. Find dimensions of D called as diffusion constant.

    A) \[2x+3y-14=0\]                

    B) \[\frac{7}{\sqrt{5}}\]

    C) \[\frac{7}{\sqrt{13}}\]                   

    D) \[\sqrt{5}\]

    Correct Answer: D

    Solution :

    Given, number of particle passing from unit area in unit time = n \[N{{H}_{2}}N{{H}_{2}}\] \[{{C}_{6}}{{H}_{5}}CHO\]Number of particle in unit volume \[\alpha \text{-}H,\] Now, from the given formula \[\underset{Acrylonitrile}{\mathop{nC{{H}_{2}}=\underset{CN}{\overset{CH}{\mathop{|}}}\,}}\,\xrightarrow[{}]{Polymerisation}{{\left( \underset{Polyacrylonitrile}{\mathop{C{{H}_{2}}-\underset{\begin{smallmatrix}  | \\  CN \end{smallmatrix}}{\mathop{CH}}\,-}}\, \right)}_{n}}\] \[{{S}_{N}}Ar\] \[C{{l}_{2}}/FeC{{l}_{3}}\]


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