Manipal Engineering Manipal Engineering Solved Paper-2014

  • question_answer
    Given, \[{{a}_{n}}=\frac{{{n}^{2}}}{{{n}^{3}}+200}\]                       \[\frac{529}{49}\] \[\frac{8}{89}\]                 \[\frac{49}{543}\] The time constant (in [is) for the circuits I, II, III are respectively

    A) 18,8/9,4               

    B) 18,4,8/9

    C)  4, 8/9; 18            

    D) 8/9, 18, 4

    Correct Answer: D

    Solution :

    \[4\lambda \] \[C{{H}_{2}}=CHBr\] \[C{{H}_{3}}C{{H}_{2}}l\]


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