Manipal Engineering Manipal Engineering Solved Paper-2014

  • question_answer
    When \[y=|\sin x{{|}^{|x|}},\] transforms to \[\frac{dy}{dx}\]then the number to the emitted \[x=\frac{-\pi }{6}\] and \[{{\frac{2}{6}}^{\frac{-\pi }{6}}}[6\log 2-\sqrt{3}\pi ]\]particles is, respectively

    A) \[{{2}^{\frac{\pi }{6}}}[6\log 2+\sqrt{3}\pi ]\]                     

    B) \[{{\frac{2}{6}}^{-\frac{\pi }{6}}}[6\log 2+\sqrt{3}\pi ]\]

    C) \[{{x}^{x}}\]                      

    D) \[x>\frac{1}{e}\]

    Correct Answer: D

    Solution :

    \[\frac{T_{1}^{2}}{T_{2}^{2}}=?(g=10m/{{s}^{2}})\] Number of \[\frac{-4\sigma }{{{\varepsilon }_{0}}}\hat{k}\]particles emitted \[\frac{4\sigma }{{{\varepsilon }_{0}}}\hat{k}\] Number of \[\frac{-2\sigma }{{{\varepsilon }_{0}}}\hat{k}\]particles emitted \[\frac{2\sigma }{{{\varepsilon }_{0}}}\hat{k}\]


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