question_answer

The fraction of atoms of radioactive element that decays in 6 days is 7/8. The fraction that decays in 10 days will be   

A)              77/80                    

B) 71/80  

C) 31/32                    

D) 15/16 By using \[\Delta l.\] \[\Delta T\]\[\Delta l\] \[\Delta T\]\[\rho \] \[100\Omega \]\[{{f}_{1}}\] Hence,\[{{f}_{2}}\] \[n=3,{{f}_{2}}=\frac{3}{4}{{f}_{1}}\]\[n=5,{{f}_{2}}=\frac{3}{4}{{f}_{1}}\]\[n=3,{{f}_{2}}=\frac{5}{4}{{f}_{1}}\]\[n=5,{{f}_{2}}=\frac{5}{4}{{f}_{1}}\] So, fraction that decays \[{{T}_{1}}\]