Manipal Engineering Manipal Engineering Solved Paper-2014

  • question_answer
    Strongest conjugate base is

    A) \[[D]=\frac{[n][{{x}_{2}}-{{x}_{1}}]}{[{{n}_{2}}-{{n}_{1}}]}\]                        

    B) \[=\frac{[{{L}^{-2}}{{T}^{-1}}][L]}{[{{L}^{-3}}]}\]

    C) \[=[{{L}^{2}}{{T}^{-1}}]\]                              

    D) \[v=4{{t}^{3}}-2t\]

    Correct Answer: A

    Solution :

    If acid is weak, its conjugate base is strong. Greater the oxidation number of CI, stronger the acid and thus, weaker the conjugate base. \[\frac{n(n+1)}{12}\] Oxidation number of Cl and acid strength increases\[\frac{(n+1)(n+5)}{12}\] Conjugate base strength increases. Hence, \[\frac{(n+1)(n-5)}{12}\] is the strongest base.


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