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Manipal Engineering Manipal Engineering Solved Paper-2012

  • question_answer
    The ratio of magnetic moments of two short magnets which give null deflection in\[\tan B\]position at\[12\,\,cm\]and\[18\,\,cm\]from the centre of a deflection magnetometer is

    A)  2 : 3                                      

    B)  8 : 27

    C)  27 : 8                    

    D)         4 : 9

    Correct Answer: B

    Solution :

    According to question,                 \[\frac{{{M}_{1}}}{d_{1}^{3}}=\frac{{{M}_{2}}}{d_{2}^{3}}\] \[\Rightarrow \]               \[\frac{{{M}_{1}}}{{{M}_{2}}}={{\left( \frac{{{d}_{1}}}{{{d}_{2}}} \right)}^{3}}={{\left( \frac{12}{18} \right)}^{3}}\] \[\therefore \]  \[\frac{{{M}_{1}}}{{{M}_{2}}}=\frac{8}{27}\]


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