A) \[_{6}{{C}^{14}},\,{{\,}_{7}}{{N}^{14}},\,{{\,}_{9}}{{N}^{19}}\]
B) \[_{6}{{C}^{14}},\,{{\,}_{7}}{{N}^{15}},\,{{\,}_{9}}{{F}^{17}}\]
C) \[_{6}{{C}^{14}},\,{{\,}_{7}}{{N}^{14}},\,{{\,}_{9}}{{F}^{17}}\]
D) \[_{6}{{C}^{12}},\,{{\,}_{7}}{{N}^{14}},\,{{\,}_{9}}{{F}^{19}}\]
Correct Answer: B
Solution :
Isotonic species have the same the number of neutrons. No. of neutrons in \[_{6}{{C}^{14}}=14-6=8\] \[_{7}{{N}^{14}}=14-7=7\] \[_{9}{{N}^{19}}=19-9=10\] \[_{7}{{N}^{15}}=15-7=8\] \[_{9}{{F}^{17}}=15-7=8\] \[_{6}{{C}^{12}}=12-6=6\] Hence,\[_{6}{{C}^{14}},\,{{\,}_{7}}{{N}^{15}},\,{{\,}_{9}}{{F}^{17}}\]are isotonic.
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