Manipal Engineering Manipal Engineering Solved Paper-2011

  • question_answer
    The time taken by AC of 50 Hz in reaching from zero to the maximum value is

    A) \[50\times {{10}^{-3}}s\]                             

    B)  \[5\times {{10}^{-3}}s\]

    C) \[1\times {{10}^{-3}}s\]                

    D)        \[2\times {{10}^{-3}}s\]

    Correct Answer: B

    Solution :

    The time taken by\[AC\]in reaching from zero to maximum value is                 \[t=\frac{1}{4}=\frac{1}{4f}\] \[=\frac{1}{50\times 4}=5\times {{10}^{-3}}s\]


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