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Manipal Engineering Manipal Engineering Solved Paper-2009

  • question_answer
    The magnetic moment of a transition metal ion is\[\sqrt{15}\,\,BM\]. Therefore, the number of unpaired electrons present in it, is

    A)  3                                            

    B)         4

    C)         1                                            

    D)         2

    Correct Answer: A

    Solution :

    \[\mu =\sqrt{n(n+2)}\] \[\Rightarrow \]               \[\sqrt{15}=\sqrt{n(n+2)}\] \[\therefore \]  \[n=3\]


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