Manipal Engineering Manipal Engineering Solved Paper-2009

  • question_answer
    Excess of carbon dioxide is passed through\[50\,\,mL\]of\[0.5\,\,M\]calcium hydroxide solution. After the completion of the reaction, the solution was evaporated to dryness. The solid calcium carbonate was completely neutralized with\[0.1\,\,N\]hydrochloric acid. The volume of hydrochloric acid required is (Atomic mass of calcium = 40)

    A) \[300\,\,c{{m}^{3}}\]

    B)                        \[200\,\,c{{m}^{3}}\]

    C) \[500\,\,c{{m}^{3}}\]     

    D)        \[400\,\,c{{m}^{3}}\]

    Correct Answer: C

    Solution :

    No. of millimoles of\[Ca{{(OH)}_{2}}=50\times 0.5=25\] No. of millimples of\[CaC{{O}_{3}}=25\] No. of milliequivalents of\[CaC{{O}_{3}}=50\] \[\therefore \]Volume of\[0.1\,\,N\,\,HCl=\frac{50}{0.1}=500\,\,c{{m}^{3}}\]


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