Solved papers for JEE Main & Advanced AIEEE Solved Paper-2012
done AIEEE Solved Paper-2012 Total Questions - 1
question_answer1) A liquid in a beaker has temperature \[\theta (t)\] at time t and \[{{\theta }_{0}}\] is temperature of surroundings, then according to Newton's law of cooling the correct graph between \[{{\log }_{e}}(\theta -{{\theta }_{0}})\] and t is :
AIEEE Solved Paper-2012