Solved papers for JEE Main & Advanced JEE Main Paper (Held On 11 April 2014)

done JEE Main Paper (Held On 11 April 2014) Total Questions - 1

• question_answer1) If \[2\cos \theta +\sin \theta =1\left( \theta \ne \frac{\pi }{2} \right),\]then \[7\cos \theta +6\sin \theta \]is equal to:   [JEE Main Online Paper ( Held On 11 Apirl  2014 )
  A)
  \[\frac{1}{2}\]                                   
  done clear
  B)
  2
  done clear
  C)
  \[\frac{11}{2}\]                                
  done clear
  D)
  \[\frac{46}{5}\]
  done clear
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