JIPMER Jipmer Medical Solved Paper-2014

  • question_answer
    An electron is moving in Bohrs fourth orbit. Its de-Broglie wavelength is \[\lambda \]. What is the circumference of the fourth orbit?

    A)  \[\frac{2}{\lambda }\]                                  

    B)     \[2\lambda \]                  

    C)     \[4\lambda \]  

    D)     \[\frac{4}{\lambda }\]

    Correct Answer: C

    Solution :

                    According to Bohrs atomic concept, an electron always move in the orbit with angular momentum is integral multiple of\[\frac{h}{2\pi }\] \[mvr=\frac{nh}{2\pi }\] \[r=\frac{nh}{2\pi mv}=\frac{n\lambda }{2\pi }\]               \[\left\{ \because \,\,\lambda =\frac{h}{mv} \right\}\] for,         \[n=4\]                 \[r=\frac{4\lambda }{2\pi }\Rightarrow \frac{2\lambda }{\pi }\] Circumference\[=2\pi r=2\pi \frac{2\lambda }{\pi }=4\lambda .\]             


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