A) \[A{{g}^{+}}\]
B) \[C{{u}^{2+}}\]
C) \[C{{d}^{2+}}\]
D) \[P{{b}^{2+}}\]
Correct Answer: D
Solution :
Ammonia is a Lewis base. It forms complexes with transition elements like \[A{{g}^{+}},\,C{{u}^{2+}}\]and \[C{{d}^{2+}}\] while it does not form complex with \[P{{b}^{2+}}\] because \[Pb\] is not a transition element. \[AgCl+2N{{H}_{4}}OH\to [Ag{{(N{{H}_{3}})}_{2}}]\,Cl+2{{H}_{2}}O\] \[CuS{{O}_{4}}+4N{{H}_{4}}OH\to [Cu{{(N{{H}_{3}})}_{4}}]\,S{{O}_{4}}+4{{H}_{2}}O\] \[CdS{{O}_{4}}+4N{{H}_{4}}OH\to [Cd{{(N{{H}_{3}})}_{4}}]\,S{{O}_{4}}+4{{H}_{2}}O.\]
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