A) \[C{{o}^{2+}}\]
B) \[N{{i}^{2+}}\]
C) \[C{{u}^{2+}}\]
D) \[Z{{n}^{2+}}\]
Correct Answer: D
Solution :
Transition metal ion having absence of unpaired electron is diamagnetic. (a) \[C{{o}^{2+}}=[Ar]\,3{{d}^{7}}\](three unpaired electrons) (b) \[N{{i}^{2+}}=[Ar]\,3{{d}^{8}}\](two unpaired electrons) (c) \[C{{u}^{2+}}=[Ar]\,3{{d}^{9}}\] (one unpaired electron) (d) \[Z{{n}^{2+}}=[Ar]\,3{{d}^{10}}\](no unpaired electron) Thus, \[Z{{n}^{2+}}\]is diamagnetic.
You need to login to perform this action.
You will be redirected in
3 sec
