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JIPMER Jipmer Medical Solved Paper-2012

  • question_answer
                                                                              The ratio of the difference in energy between the first and the second Bohr orbit to that between the second and the third Bohr orbit is

    A) 1/2  

    B)                                        1/3                        

    C)        4/9                                        

    D)        27/5

    Correct Answer: D

    Solution :

    \[\Delta E={{E}_{2}}-{{E}_{1}}=\frac{1312}{{{1}^{2}}}-\frac{1312}{{{2}^{2}}}=1312\left( \frac{3}{4} \right).\] \[{{E}_{3}}-{{E}_{2}}=\frac{1312}{{{2}^{2}}}-\frac{1312}{{{3}^{2}}}=1312\left( \frac{5}{36} \right)\] \[\therefore \]\[{{E}_{2}}-{{E}_{1}}:{{E}_{3}}-{{E}_{2}}=\frac{3}{4}:\frac{5}{36}=27:5.\]


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