A) \[3.0\times {{10}^{-3}}{{s}^{-1}}\]
B) \[2.8\times {{10}^{-4}}{{s}^{-1}}\]
C) \[17.2\times {{10}^{-3}}{{s}^{-1}}\]
D) \[1.8\times {{10}^{-3}}{{s}^{-1}}\]
Correct Answer: B
Solution :
For a first order reaction, \[k=\frac{2.303}{1.386\times 60\times 60}\log \frac{a}{a-0.75\,a}\] \[=\frac{2.303}{1.386\times 60\times 60}\log 4\] \[=2.8\times {{10}^{-4}}\,{{s}^{-1}}.\]
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