question_answer

The work done by a force acting on a body is as shown in the graph. The total work done in covering an initial distance of 20 m is

A)  225 J

B)                                         200 J

C)  400 J                    

D)         175 J

Correct Answer: B

Solution :

Work done (W) = Area (ABCEFDA) = Area ABCD + Area CEFD \[=\frac{1}{2}\times (15+10)\times 10+\frac{1}{2}\times (10+20)\times 5\] \[=125+75=200\,J.\]