A) \[\frac{n}{d(n+\sqrt{2})}\]
B) \[\frac{d(n+\sqrt{2})}{n\sqrt{2}}\]
C) \[\frac{\sqrt{2}n}{d(n+\sqrt{2})}\]
D) \[\frac{nd}{d+\sqrt{2}n}\]
Correct Answer: B
Solution :
Refractive index\[\mu =\frac{\text{Real}\,\,\text{depth}\,\text{(d)}}{\text{Apparent}\,\,\text{depth}\,\text{(x)}}\] For 1st refraction,\[\sqrt{2}=\frac{d}{{{x}_{1}}}\,\,\,\Rightarrow \,\,\,{{x}_{1}}=\frac{d}{\sqrt{2}}\] For 2nd refraction \[n=\frac{d}{{{x}_{2}}}\,\,\,\Rightarrow \,\,{{x}_{2}}=\frac{d}{n}\] Apparent depth\[={{x}_{1}}+{{x}_{2}}=\frac{d}{\sqrt{2}}+\frac{d}{n}\] \[=\frac{d(n+\sqrt{2})}{n\sqrt{2}}\]
You need to login to perform this action.
You will be redirected in
3 sec
