A) 96 J
B) 216 J
C) 144 J
D) 360 J
Correct Answer: A
Solution :
Ratio of the masses of the fragments = 2:3 So, masses of the fragments are 8 kg and 12 kg. From conservation of momentum \[{{m}_{1}}{{v}_{1}}={{m}_{2}}{{v}_{2}}\] \[8\times 6=12\times v\] \[v=\frac{8\times 6}{12}=4\,m\text{/}\sec \] \[K.E.=\frac{1}{2}m{{v}^{2}}\] \[=\frac{1}{2}\times 12\times {{(4)}^{2}}=96\,J.\]You need to login to perform this action.
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