A) \[{{\sin }^{-1}}(0.01)\]
B) \[{{\sin }^{-1}}(0.0001)\]
C) \[{{\sin }^{-1}}(0.001)\]
D) \[{{\sin }^{-1}}(0.1)\]
Correct Answer: C
Solution :
According to the Youngs double slit experiment half angular width is given by \[\sin \,(\theta )=\frac{\lambda }{d}\] \[=\frac{589\times {{10}^{-9}}}{0.589\times {{10}^{-3}}}={{10}^{-3}}\] \[\theta ={{\sin }^{-1}}({{10}^{-3}}).\]
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