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JIPMER Jipmer Medical Solved Paper-2012

  • question_answer
    A wheel of radius 0.4 m can rotate freely about its axis as shown in the figure. A string is wrapped over its rim and a mass of 4 kg is hung. An angular acceleration of 8 \[\text{rad-}{{\text{s}}^{-2}}\]s is produced in it due to the torque. Then, moment of inertia of the wheel is \[\text{(g}\,\text{=}\,\text{m}{{\text{s}}^{-2}})\]

    A)  2 kg-\[{{\text{m}}^{2}}\]        

    B)  1 kg-\[{{\text{m}}^{2}}\]

    C)  4 kg-\[{{\text{m}}^{2}}\]        

    D)         8 kg-\[{{\text{m}}^{2}}\]

    Correct Answer: A

    Solution :

                    Given data m = 4 kg, r = 0.4 m, \[\alpha \] = 8 rad/\[{{\sec }^{2}}\] Torque        \[Z=I.\,\alpha \]                 \[mgr=I.\,\alpha \] or, \[4\times 10\times 0.4=I\times 8\] \[I=\frac{16}{8}=2kg-{{m}^{2}}\]                 \[I=2\,kg\text{-}{{m}^{2}}.\]


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