JIPMER Jipmer Medical Solved Paper-2012

  • question_answer
    A coin is dropped in a lift. It takes time \[{{t}_{1}}\] to reach the floor when lift is stationary. It takes time \[{{t}_{2}}\] when lift is moving up with constant acceleration. Then,

    A)  \[{{t}_{1}}\ge {{t}_{2}}\]

    B)                         \[{{t}_{2}}>{{t}_{1}}\]

    C)  \[{{t}_{1}}={{t}_{2}}\]   

    D)         \[{{t}_{1}}>\,>{{t}_{2}}\]

    Correct Answer: A

    Solution :

    When lift is in rest \[{{t}_{1}}=\sqrt{\frac{2h}{g}}\] and when the lift is moving up with constant acceleration \[{{t}_{2}}=\sqrt{\frac{2{{h}_{1}}}{g}}\] Here, \[h>{{h}_{1}}\] So, \[{{t}_{1}}>{{t}_{2}}.\]


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