A) \[5I\,\,\text{and}\,\,I\]
B) \[5I\,\,\text{and}\,\,3I\]
C) \[9I\,\,\text{and}\,\,I\]
D) \[9I\,\,\text{and}\,\text{3}\,I\]
Correct Answer: C
Solution :
Given, \[{{I}_{1}}=I,\]\[{{I}_{2}}=4I\] \[{{I}_{\max }}={{(\sqrt{{{I}_{1}}}+\sqrt{{{I}_{2}}})}^{2}}\] \[={{(\sqrt{I}+\sqrt{4I})}^{2}}={{(3\sqrt{I})}^{2}}=9I\] \[{{I}_{\min }}={{(\sqrt{{{I}_{1}}}-\sqrt{{{I}_{2}}})}^{2}}={{(\sqrt{I}-\sqrt{4I})}^{2}}\] \[={{(-\sqrt{I})}^{2}}=I\]
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