JIPMER Jipmer Medical Solved Paper-2005

  • question_answer
    If work function of a metal is 4.2 eV, the cut off wavelength is:

    A)  \[8000\text{ { }\!\!\mathrm{\AA}\!\!\text{ }}\]   

    B)                         \[7000\text{ { }\!\!\mathrm{\AA}\!\!\text{ }}\]

    C)         \[1472\text{ { }\!\!\mathrm{\AA}\!\!\text{ }}\]               

    D)         \[2950\text{ { }\!\!\mathrm{\AA}\!\!\text{ }}\]

    Correct Answer: D

    Solution :

    Suppose the cut off wavelength is represented by \[{{\lambda }_{0}}\] So, \[\frac{hc}{{{\lambda }_{0}}}=\] work function\[={{W}_{0}}\] \[\frac{hc}{{{\lambda }_{0}}}=4.2\times 1.6\times {{10}^{-19}}\] \[{{\lambda }_{0}}=\frac{6.6\times {{10}^{-34}}\times 3\times {{10}^{8}}}{4.2\times 1.6\times {{10}^{-19}}}\] \[=2946\times {{10}^{-10}}m\] \[=2950\,\overset{\text{o}}{\mathop{\text{A}}}\,\]


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