A) 711 \[\mu F\]
B) 611\[\mu F\]
C) 811 \[\mu F\]
D) 511\[\mu F\]
Correct Answer: A
Solution :
Here: Diameter of earth \[=12.8\times {{10}^{3}}km\] So, radius \[R=\frac{12.8}{2}\times {{10}^{3}}\] \[=6.4\times {{10}^{3}}km=6.4\times {{10}^{6}}m\] Capacity \[C=4\pi {{\varepsilon }_{0}}R\] \[=\frac{1}{9\times {{10}^{9}}}\times 6.4\times {{10}^{6}}\] \[=711\times {{10}^{-6}}F=711\mu F\]
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