JIPMER Jipmer Medical Solved Paper-2003

  • question_answer
    Vapour density of a volatile substance is \[4(C{{H}_{4}}=1)\]. Its molecular weight would be:

    A)  2                                            

    B)  8                            

    C)  64                         

    D)         128

    Correct Answer: C

    Solution :

    Actual vapour density of methane \[=\frac{mol\,.\,wt}{2}=\frac{16}{2}=8\] \[\therefore \] vapour density of volatile substance \[=8\times 4=32\] Molecular weight of the substance \[=32\times 2=64\]


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