JIPMER Jipmer Medical Solved Paper-2003

  • question_answer
    Acceleration due to gravity at earths surface is\[g\text{ }m{{s}^{-2}}\]. Find the effective value of gravity at a height of 32 km from sea level: (\[{{R}_{e}}\] = 6400 km)

    A)  \[0.5g\,\text{m}{{\text{s}}^{\text{-2}}}\]           

    B)         \[0.99g\,\text{m}{{\text{s}}^{\text{-2}}}\]         

    C)         \[1.01g\,\text{m}{{\text{s}}^{\text{-2}}}\]         

    D)         \[0.90g\,\text{m}{{\text{s}}^{\text{-2}}}\]

    Correct Answer: B

    Solution :

    For height \[h\] above the earths surface \[g=g\left( 1-\frac{2h}{{{R}_{e}}} \right)=g\left( 1-\frac{64}{6400} \right)\] \[(\because \,{{R}_{e}}=6400\,km)\] \[=g(1-0.01)=0.99\,g\,m{{s}^{-2}}\]


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