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JIPMER Jipmer Medical Solved Paper-2003

  • question_answer
    If an electron has orbital angular momentum quantum number \[l=7\] then it will have an orbital angular momentum equal to:

    A)  \[\sqrt{56}\left( \frac{h}{2\pi } \right)\]               

    B)         \[57\left( \frac{h}{2\pi } \right)\]            

    C)         \[42\left( \frac{h}{2\pi } \right)\]            

    D)         \[7\left( \frac{h}{2\pi } \right)\]

    Correct Answer: A

    Solution :

    \[L=\sqrt{l(l+1)}\cdot \frac{h}{2\pi }=\sqrt{7\times 8}\frac{h}{2\pi }=\sqrt{56}\frac{h}{2\pi }\]


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