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JIPMER Jipmer Medical Solved Paper-2003

  • question_answer
    Standing wave are produced in a 10 m long stretched string. If the string vibrates in 5 segments and the wave velocity is 20 m/s. The frequency is:

    A)  10 Hz                   

    B)         5 Hz                      

    C)  4 Hz                      

    D)         2 Hz

    Correct Answer: B

    Solution :

    \[n=\frac{p}{2l}\sqrt{\frac{T}{m}}=\frac{pv}{2l}=\frac{5\times 20}{2\times 10}=5\,Hz\]


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