A)
\[1\mu F\]
B) \[2\mu F\]
C) \[1.5\mu F\]
D) \[3\mu F\]
Correct Answer: A
Solution :
From the figure \[1.5\mu F\] and \[1.5\mu F\] are in parallel. Hence, equivalent capacitance is \[{{C}_{p}}=1.5+1.5=3\mu F\] Again these condensers are connected in series. So, \[\frac{1}{{{C}_{s}}}=\frac{1}{3}+\frac{1}{3}+\frac{1}{3}=1,\] So, \[{{C}_{s}}=1\mu F\]
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