A) +3
B) +2
C) +4
D) +7
Correct Answer: D
Solution :
\[{}_{25}Mn\]has electronic configuration \[=1{{s}^{2}},2{{s}^{2}}2{{p}^{6}},3{{s}^{2}}3{{p}^{6}}3{{d}^{5}},4{{s}^{2}}.\] It can show + 7 oxidation state by loosing all the seven electrons in 3d and 4s-sub-shells.
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